Vector Valued Function

When working with objects moving through space, it makes sense to consider them moving over a certain amount of time, \(t.\) Time could be drawn as another dimension on a graph, but most of the time this is unnecessary since time always carries on in the same way (assuming your not dealing with anything traveling near the speed of light.) For this reason, it is often useful to define the position on the \(x\) and \(y\) axis using time, but not writing time as a third axis. This is something that does not work so well with Cartesian equations but is much simpler using vector-valued functions, hence making them incredibly useful in Physics, Machine Learning, and many other subjects.

Get started

Millions of flashcards designed to help you ace your studies

Sign up for free

Achieve better grades quicker with Premium

PREMIUM
Karteikarten Spaced Repetition Lernsets AI-Tools Probeklausuren Lernplan Erklärungen Karteikarten Spaced Repetition Lernsets AI-Tools Probeklausuren Lernplan Erklärungen
Kostenlos testen

Geld-zurück-Garantie, wenn du durch die Prüfung fällst

Review generated flashcards

Sign up for free
You have reached the daily AI limit

Start learning or create your own AI flashcards

StudySmarter Editorial Team

Team Vector Valued Function Teachers

  • 10 minutes reading time
  • Checked by StudySmarter Editorial Team
Save Article Save Article
Contents
Contents

Jump to a key chapter

    Vector-Valued Function Definition

    Before you get into the details of vector-valued functions, it is important to understand vectors fully.

    Vectors

    A vector is a mathematical object that has both direction and magnitude.

    Vector-Values Functions A vector represented by an arrow StudySmarterFig. 1. A vector can be thought of like an arrow, pointing from one place to another.

    Vectors can be written in two different ways,

    • Column Vector Form: \( \begin{bmatrix} x \\ y \end{bmatrix}, \)

    • Component Form: \( x \vec{i} + y \vec{j}. \)

    These two vectors are equivalent. Numerically, vectors can be added and subtracted by adding or subtracting the individual components. Similarly, they can be multiplied by scalar quantities by multiplying the individual components. In component form, this looks just like collecting like terms and expanding brackets.

    Graphically, adding vectors is done by stacking them tip to tip, and subtracting by stacking them tip to tip, but pointing the second vector in the opposite direction. Multiplying numbers by a scalar \(\lambda\) is the same as stacking \(\lambda\) of the same vectors, tip to tip, and if \(\lambda\) is negative, the product will be pointing in the opposite direction.

    Finally, given a vector \( v = x \vec{i} + y \vec{j},\) the magnitude \(|\vec{v}|\) and direction angle \(\theta\) of a vector can be calculated using the following formulas:

    \[ \begin{align} | \vec{v} | & = \sqrt{ x^2 + y^2 }, \\ \theta & = \tan^{-1}\left({\frac{x}{y}}\right) \end{align} \]

    For more information on all of this, see Vectors.

    What are Vector-Valued Functions?

    Vector-valued functions are just like real-valued functions, but output a vector instead of a scalar.

    A vector-valued function is a function that takes a scalar value as input, and gives a vector as output. A vector-valued function of one variable looks like this,

    \[ \vec{r}(t) = \begin{bmatrix} f(t) \\ g(t) \end{bmatrix} = f(t) \vec{i} + g(t) \vec{j}. \]

    Here, \( f(t)\) and \(g(t)\) are parametric equations.

    Given this definition, you can deduce the domain and range of a vector-valued function.

    • The domain of a vector-valued function is a subset of \(\mathbb{R},\)

    • The range of an \(n\)-dimensional vector-valued function is a subset of \(\mathbb{R}^n.\)

    Here you will focus on vectors in 2 dimensions, meaning the range of the functions will be a subset of \(\mathbb{R}^2.\) It is important to note that it is a subset of \(\mathbb{R}^2\) and not the whole of \(\mathbb{R}^2,\) since you will encounter many vector-valued functions that cannot output to every point in \(\mathbb{R}^2.\)

    Examples of Vector-Valued Functions

    There are many different types of vector-valued functions, but here you will look at some of the simplest.

    Straight Lines

    The vector-valued formula for a straight line is

    \[ \vec{r}(t) = \begin{bmatrix} a_1 \\ a_2 \end{bmatrix} + t \begin{bmatrix} b_1 \\ b_2 \end{bmatrix}. \]

    Here, \(\vec{a} = a_1 \vec{i} + a_2 \vec{b} \) is the position vector of a point \(a\) on the line, and \( \vec{b} = b_1 \vec{i} + b_2 \vec{j} \) is a vector that is parallel to the line.

    Vector-valued functions A line with a point on it labelled a, and a parallel vector labeled b StudySmarterFig. 2. A line is defined by a vector-valued function using a point on the line, \(a,\) and a vector parallel to the line, \(\vec{b}.\)

    Circles and Ellipses

    The vector-valued equation for a circle with radius \(a\) is

    \[ \vec{r}(t) = \begin{bmatrix} a \cos{t} \\ a \sin{t} \end{bmatrix} \]

    Vector-valued functions a circle with radius a, and points on the curve labelled a cosine t, a sine t StudySmarterFig. 3. The vector-valued function for a circle can be made using the sine and cosine functions.

    An ellipse can be defined similarly, but using \(a\) as the intercept on the \(x\)-axis and \(b\) as the intercept on the \(y\)-axis.

    \[ \vec{r}(t) = \begin{bmatrix} a \cos{t} \\ b \sin{t} \end{bmatrix} \]

    Vector-valued functions A circle with intercepts a and b on the x and y axis, with lengths a cosine t and b sine t going from each axis to the ellipse StudySmarterFig. 4. The vector-valued function for an ellipse can be defined similarly to that of a circle, but taking into account the different axis intercepts.

    Spirals

    There are many ways to define spirals in mathematics, but an easy way is to define them similarly to spirals and circles, but with a \(t\) term in front of the trigonometric functions.

    \[ \vec{r}(t) = \begin{bmatrix} a t \cos{t} \\ b t \sin{t} \end{bmatrix} \]

    Vector-valued Functions A line spiraling outwards from the origin StudySmarterFig. 5, The graph of an spiral, where \(a = b = \frac{1}{2}. \)

    Graphing Vector-Valued Functions

    When you first learnt to graph Cartesian equations such as \(y = f(x),\) you likely started by drawing a table of values for \(x,\) and then filling in the corresponding values of \(y.\) You could then plot these points and join them up, to create an estimation of the curve. You can do the exact same thing to graph vector-valued functions, but instead starting with the variable \(t\) and using these values of \(t\) to calculate the corresponding values of \(x\) and \(y.\) Let's look at an example of this.

    Sketch the graph of \( \vec{r} = t^2 \vec{i} + t \vec{j}, \) for values of \(-4 < t < 4. \)

    Solution

    First, create a table with three columns, titled \(t, x, y.\) You can fill in the \(t\) column with the integers from \(-4\) to \(4.\)

    \(t\)\(x\)\(y\)
    -4
    -3
    -2
    -1
    0
    1
    2
    3
    4

    From here, you can start filling in the values. Remember that \(x\) will be the coefficient of the \(\vec{i}\) term, and \(y\) will be the coefficient of the \(\vec{j}\) term. First, let's fill in the \(x\) column by squaring all of the values in the \(t\) column.

    \(t\)\(x\)\(y\)
    -416
    -39
    -24
    -11
    00
    11
    24
    39
    416

    Next, fill in the \(y\) column. This will be exactly the same as the values on the \(t\) column.

    \(t\)\(x\)\(y\)
    -416-4
    -39-3
    -24-2
    -11-1
    000
    111
    242
    393
    4164

    Next, plot the \((x,y)\) pairs on a graph.

    Vector-valued functions the points make the shape of a parabola going in the positive x direction StudySmarterFig. 6. The shape of these dots seems to resemble a parabola.

    Based on the shape of the plotted points and the fact that the function has a \(t^2\) term in it, it appears to be a parabola. You can draw a curve between these points to get the following curve:

    Vector-valued functions The parabola x = y squared, for values of x between -4 and 4 StudySmarterFig. 7. The finished curve is the parabola \(x = y^2.\)

    To see more examples, see Graphing Vector-Valued Functions.

    Vector-Valued Functions Formula

    The most important formula for vector-valued functions is the formula for arc length, or the length of a curve between two points.

    Vector-valued Functions a curve with the length between t = a and t = b highlighted StudySmarterThe length of the curve between the points \(t=a\) and \(t=b.\)

    The length \(L\) of a curve \(\vec{r}(t) = f(t) \vec{i} + g(t) \vec{j} \) between two point \(a\) and \(b\) is

    \[ L = \int_a^b \sqrt{[f'(t)]^2 + [g'(t)]^2} \, \mathrm{d}t. \]

    This measures the whole length of the curve as if you had laid a piece of string on the curve and then cut it off and measured it. Let's look at some examples using this formula.

    Find the arc length of

    \[ \vec{r} = \begin{bmatrix} \sin{(3t)} \\ \cos{(3t)} \end{bmatrix} \]

    for \(-4 < t < 2.\)

    Solution

    Here, \(f(t) = \sin{(3t)}\) and \(g(t) = \cos{(3t)}.\) The formula requires the derivatives of these functions, so you must differentiate them both.

    \[ \begin{align} f'(t) & = 3 \cos{(3t)} \\ g'(t) & = 3 \sin{(3t)}. \end{align} \]

    From here, you can substitute these into the formula for the arc length.

    \[ \begin{align} L & = \int_{-4}^{2} \sqrt{(3 \cos{(3t)})^2 + (3 \sin{(3t)})^2} \, \mathrm{d}t \\ & = \int_{-4}^2 \sqrt{ 9 \cos^2{(3t)} + 9 \sin^2{(3t)} } \, \mathrm{d}t \\ & = \int_{-4}^{2} \sqrt{9 (\cos^2{(3t)} + \sin^2{(3t)})} \, \mathrm{d}t. \end{align} \]

    From here, you can use the formula \(\sin^2{x} + \cos^2{x} = 1. \)

    \[ \begin{align} L & = \int_{-4}^{2} \sqrt{9 \cdot 1} \, \mathrm{d}t \\ & = \int_{-4}^{2} 3 \, \mathrm{d}t \\ & = [3t]_{-4}^{2} \\ & = 3\cdot 2 - 3 \cdot (-4) \\ & = 18. \end{align} \]

    Hence, the arc length is 18 unit length.

    Derivatives of Vector-Valued Function

    The derivative of vector-valued functions can be found by differentiating each component of the vector-valued function. The derivative of \( \vec{r}(t) = f(t) \vec{i} + g(t) \vec{j} \) is:

    \[ \frac{\mathrm{d}\vec{r}}{\mathrm{d}t}(t) = \frac{\mathrm{d}f}{\mathrm{d}t}(t) \vec{i} + \frac{\mathrm{d}g}{\mathrm{d}\mathrm{d}}(t) \vec{j}, \]

    assuming that the derivatives of \(f(t)\) and \(g(t)\) with respect to \(t\) exist. This makes sense logically, as it is just like using the addition rule when differentiating any other function. The derivative of a vector-valued function at a point will point in the direction of travel of the function, at a tangent to the curve.

    If the vector valued function, call it \(\vec{s}(t),\) represents position on the \(xy\) plane at time \(t,\) then the derivative of this function will be the velocity vector \(\vec{v}(t).\) The magnitude of the velocity vector at time \(t\) is the speed of travel at time \(t.\) Similarly, the differential of the velocity vector will be the acceleration vector, \( \vec{a}(t). \) Let's take a look at differentiating some vector-valued functions.

    A particle's position in space is given by the vector-valued function

    \[ \vec{s}(t) = \begin{bmatrix} 3t^2 \\ e^t \end{bmatrix}. \]

    Find the vector-valued functions for the velocity and acceleration of the particle.

    Solution

    If you differentiate the position function, you will get the velocity function. This will be,

    \[ \vec{v}(t) = \vec{s}'(t) = \begin{bmatrix} 6t \\ e^t \end{bmatrix}. \]

    Next, you can differentiate this again to find the acceleration function.

    \[ \vec{a}(t) = \vec{v}'(t) = \begin{bmatrix} 6 \\ e^t \end{bmatrix}. \]

    To learn more about differentiating vector-valued functions, see Calculus of Vector-Valued Functions.

    Vector Valued Function - Key takeaways

    • A vector-valued function is a function that takes a scalar value as input, and gives a vector as an output.
    • Vector-valued functions can be written \( \vec{r}(t) = f(t) \vec{i} + g(t) \vec{j}. \)
    • The domain of a vector-valued function is a subset of \(\mathbb{R}\).

    • The range of an \(n\)-dimensional vector-valued function is a subset of \(\mathbb{R}^n.\)

    Learn faster with the 0 flashcards about Vector Valued Function

    Sign up for free to gain access to all our flashcards.

    Vector Valued Function
    Frequently Asked Questions about Vector Valued Function

    How do you write a vector-valued function? 

    vector valued functions can be written as:

    r(t) = f(t) i + g(t) j,

    where f(t) and g(t) are scalar functions.

    What are the components of a vector-valued function?

    A vector valued function written as:
    r(t) = f(t) i + g(t) j.

    The components of this are:

    • The unit vectors i and j,
    • The scalar functions f(t) and g(t).

    How do you tell if a function is vector valued or scalar valued? 

    A vector valued function will have the range of Rn, where n is the dimension of the vector output. A scalar function will always output a scalar result, so it's range is just R. 

    What is a vector valued equation? 

    A vector valued function or equation is an equation that takes a scalar value as input and outputs a vector value. 

    How do you graph a vector-valued function in geogebra? 

    A vector-valued function such as:

    r(t) = f(t) i + g(t) j 

    can be graphed in GeoGebra by writing:

    (f(t), g(t)).

    Save Article

    Discover learning materials with the free StudySmarter app

    Sign up for free
    1
    About StudySmarter

    StudySmarter is a globally recognized educational technology company, offering a holistic learning platform designed for students of all ages and educational levels. Our platform provides learning support for a wide range of subjects, including STEM, Social Sciences, and Languages and also helps students to successfully master various tests and exams worldwide, such as GCSE, A Level, SAT, ACT, Abitur, and more. We offer an extensive library of learning materials, including interactive flashcards, comprehensive textbook solutions, and detailed explanations. The cutting-edge technology and tools we provide help students create their own learning materials. StudySmarter’s content is not only expert-verified but also regularly updated to ensure accuracy and relevance.

    Learn more
    StudySmarter Editorial Team

    Team Math Teachers

    • 10 minutes reading time
    • Checked by StudySmarter Editorial Team
    Save Explanation Save Explanation

    Study anywhere. Anytime.Across all devices.

    Sign-up for free

    Sign up to highlight and take notes. It’s 100% free.

    Join over 22 million students in learning with our StudySmarter App

    The first learning app that truly has everything you need to ace your exams in one place

    • Flashcards & Quizzes
    • AI Study Assistant
    • Study Planner
    • Mock-Exams
    • Smart Note-Taking
    Join over 22 million students in learning with our StudySmarter App
    Sign up with Email