Quadrilaterals

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Contents
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  • Last Updated: 20.02.2023
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Road sign and coloured paper example, StudySmarter Originals

Road sign and coloured paper example, StudySmarter Originals

Do you see any resemblances between this road sign and each sheet of paper? As a matter of fact, there are two similarities we can spot here! First of all, both objects have exactly four sides. Secondly, they have precisely four corners on each side. You may now be wondering, what kind of shape might have such properties and if so, what are they called? To answer your question, these shapes are called quadrilaterals!

In this discussion, we shall be introduced to a particular type of polygon known as a quadrilateral. Here, we shall look at the different types of quadrilaterals while studying their properties, perimeter and area formulas.

What is a Quadrilateral?

The abbreviation "quad" describes something that is in terms of four. For example, a mother carrying four babies in one pregnancy will be expecting the birth of quadruplets. In geometry, this contraction is found in the term quadrilateral, which adopts the same idea. Let's define it below.

A quadrilateral is a polygon with four sides, four vertices and four angles.

Recall that a polygon is a two-dimensional geometric figure with a finite number of sides.

The sides (or edges) of a polygon are made up of straight-line segments joined together end to end. The point at which a pair of line segments meet is called the vertex (or corner).

The term quadrilateral stems from two Latin words: quadri (a variant of four) and latus (side). There are two other names that describe a quadrilateral, namely

  1. A tetragon which is derived from the Greek words tetra and gon meaning four and angle (or corner), respectively;
  2. A quadrangle since it has four angles.

Naming a Quadrilateral

It is important to note that the order of the vertices for a given quadrilateral must be taken into account when naming a quadrilateral. Here is an example.

Naming a quadrilateral, StudySmarter Originals

Naming a quadrilateral, StudySmarter Originals

The quadrilateral above has sides PQ, QR, RS and SP and vertices P, Q, R and S. The diagonals are described by PR and QS.

This quadrilateral can be denoted by PQRS, QRSP, RSPQ or SPQR. However, we cannot call it SQPR or RPQS, for example since the order of the vertices here is incorrect.

Types of Quadrilaterals

There are six types of quadrilaterals we should familiarise ourselves with throughout this topic. This is described in the table below.

Quadrilateral

Visual Representation

Square

Square, StudySmarter Originals

Square, StudySmarter Originals

Rectangle

Rectangle, StudySmarter Originals

Rectangle, StudySmarter Originals

Parallelogram

Parallelogram, StudySmarter Originals

Parallelogram, StudySmarter Originals

Trapezium

Trapezium, StudySmarter Originals

Trapezium, StudySmarter Originals

Rhombus

Rhombus, StudySmarter Originals

Rhombus, StudySmarter Originals

Kite

Kite, StudySmarter Originals

Kite, StudySmarter Originals

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Quadrilaterals

Properties of Quadrilaterals

Looking at our previous table, there are four characteristics all quadrilaterals have in common. Listing them below, we can say that every quadrilateral has

  1. Four sides;

  2. Four vertices;

  3. Two diagonals;

  4. The sum of all their interior angles is 360o.

Although all quadrilaterals have the same basic qualities, the measures of their sides and angles differ from one another. In the table below, we shall describe the distinct features of the six quadrilaterals introduced before.

Quadrilateral

Sides

Parallel Sides

Angles

Right Angles

Diagonals

Square

Square, StudySmarter Originals

Square, StudySmarter Originals

Has 4 equal sides

Has 2 pairs of parallel sides

Has 4 equal angles

Has 4 right angles

Has 2 equal diagonals that are perpendicular and bisect each other

Rectangle

Rectangle, StudySmarter Originals

Rectangle, StudySmarter Originals

Has opposite sides of equal length

Has 2 pairs of parallel sides

Has 4 equal angles

Has 4 right angles

Has 2 equal diagonals that bisect each other

Parallelogram

Parallelogram, StudySmarter Originals

Parallelogram, StudySmarter Originals

Has opposite sides of equal length

Has 2 pairs of parallel sides

Has opposite angles of equal measures

None

Has 2 non-equal diagonals that bisect each other

Trapezium

Trapezium, StudySmarter Originals

Trapezium, StudySmarter Originals

  • Legs: The sides that are not parallel to each other

  • If there are two equal legs, it is called an isosceles trapezium

  • Bases: The sides that are parallel to each other

  • Has one pair of parallel sides (usually the bases).

  • If there are no angles (or sides) of equal measure, it is called a scalene trapezoid.

  • If there are two opposite obtuse angles, it is called an obtuse trapezoid.

  • If there are two adjacent acute angles, it is called an acute trapezoid.

If there are two adjacent right angles, it is called a right trapezium.

Right trapezium, StudySmarter Originals

Right trapezium, StudySmarter Originals

If the diagonals are of equal lengths, it is an isosceles trapezoid.

Isosceles trapezium, StudySmarter Originals

Isosceles trapezium, StudySmarter Originals

Rhombus

Rhombus, StudySmarter Originals

Rhombus, StudySmarter Originals

Has 4 equal sides

Has 2 pairs of parallel sides

Has opposite angles of equal measures

None

Has 2 non-equal diagonals that are perpendicular and bisect each other

Kite

Kite, StudySmarter Originals

Kite, StudySmarter Originals

Has two pairs of equal adjacent sides

None

Has one pair of equal opposite angles that are obtuse

None

Has 2 non-equal diagonals that are perpendicular and bisect each other

Angles of Quadrilaterals

In this segment, we shall discuss the characteristics of the interior and exterior angles of a quadrilateral. We shall also observe some notable relationships between their opposite and adjacent angles.

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Quadrilaterals

Interior Angles of a Quadrilateral

We had mentioned before that the sum of the interior angles of a quadrilateral is 360º. Since a quadrilateral is a type of polygon, we can prove this statement by using the following formula.

Sum of Interior Angles Formula

For a polygon with n number of sides, the sum of its interior angles, S is equal to

S=(n2)×180º

Since a quadrilateral has four sides, then n=4 and so

S=(42)×180º

S=2×180º

S=360º

Thus, we have shown that all the interior angles of a quadrilateral add up to 360º.

Naming a quadrilateral, StudySmarter Originals

Interior angles of a quadrilateral, StudySmarter Originals

In the rectangle above, SPQ+PQR+QRS+RSP=360º.

Adjacent Angles of Quadrilaterals

Two angles that lie side by side are called adjacent angles. Adjacent angles often make use of two important concepts, namely

  1. Supplementary angles: Two adjacent angles are supplementary when the sum of their measures is equal to 180º.

  2. Complementary angles: Two adjacent angles are complementary when the sum of their measures is equal to 90º.

Both these ideas can be applied to quadrilaterals as well. Let us observe the rhombus below.

Supplementary angles of a quadrilateral, StudySmarter Originals

Supplementary angles of a quadrilateral, StudySmarter Originals

The straight line segment CBX is made up of ABC (interior angle of the rhombus) and ABX (exterior angle of the rhombus). The angle of a straight line is always 180º. Since ABC and ABX lie on this line and are adjacent to each other, they are supplementary angles. Say we are given CBA=114º. To find ABX, we can conduct the following calculation.

ABC+ABX=CBX

ABC+114º=180º

ABC=180º114º

ABC=66º

Thus, ABX=66º. Now, let us take a look at the rectangle below.

Naming a quadrilateral, StudySmarter Originals

Complementary angles of a quadrilateral, StudySmarter Originals

Given the properties of a rectangle, we know that each interior angle is 90º. Say RSQ=22º. We are now told to find PSQ. To do this, simply note that the sum of RSQ and PSQ equal 90º since they are adjacent and lie at a right angle. Thus, PSQ is 68º since

PSQ+RSQ=PSR

PSQ+22º=180º

PSQ=180º22º

PSQ=68º

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Quadrilaterals

Exterior Angles of a Quadrilateral

The sum of the exterior angles of any polygon equals 360º. This means that the sum of the exterior angles of a quadrilateral is also 360º. To show this, let us return to our previous rectangle and draw an extended straight line at each vertex.

Exterior angles of a quadrilateral, StudySmarter Originals

Exterior angles of a quadrilateral, StudySmarter Originals


The interior angles of this rectangle are SPQ, anglePQR, QRS and RSP, while the exterior angles are W, X, Y and Z. Notice that each interior angle corresponds to an exterior angle that is adjacent to them and lies on a straight line. Recall that the angle of a straight line is 180º. Thus, we have four sets of supplementary angles. The exterior angles in this case are also equal since the interior angles are all equal. Let's solve one of these exterior angles to prove our claim.

PQR=X=RQA

PQR+90º=180º

PQR=180º90º

PQR=90º

Since, X=Y=Z=W=90º, then X+Y+Z+W=9(90º)=360º, as required.

Vertically Opposite Angles of Quadrilaterals

Vertically opposite angles are two (opposite) angles constructed by two straight intersecting lines that extend from a pair of distinct vertices. Vertically opposite angles are always equal to each other. Refer back to our rectangle above with O being the point of intersection between the two diagonals.

Vertically opposite angles of a quadrilateral, StudySmarter Originals

Vertically opposite angles of a quadrilateral, StudySmarter Originals

Here, POQ and SOR are vertically opposite angles. Thus, POQ=SOR. Similarly, POS and QOR are vertically opposite angles and so POS=QOR. The same concept applies to squares, rectangles, parallelograms, rhombuses and kites (try it yourself!).

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Quadrilaterals

Corresponding Angles of Quadrilaterals

Corresponding angles are formed when two parallel lines are intersected by the transversal line. A transversal line is a line that crosses a pair of lines on the same plane at two specific points. Corresponding angles are always equal to each other. Let's show this with the parallelogram below.

Corresponding angles of a quadrilateral, StudySmarter Originals

Corresponding angles of a quadrilateral, StudySmarter Originals

Here, ADC (interior angle of the parallelogram) and XAB (exterior angle of the parallelogram) are corresponding angles since the line DAX passes through parallel sides AB and DC. Thus, ADC=XAB.

Similarly, BCD and YBA are corresponding angles since the line CBY crosses the parallel sides AD and BC. Therefore, BCD=YBA. This concept applies to squares, rectangles and rhombuses as well (give it a go!).

Perimeter of Quadrilaterals

The perimeter of a quadrilateral is defined as the total length of its boundary. In other words, it is the sum of all its sides. Therefore, for a quadrilateral ABCD

The perimeter of quadrilaterals, StudySmarter Originals

The perimeter of quadrilaterals, StudySmarter Originals

with sides AB, BC, CD and DA, the perimeter, P is

P=AB+BC+CD+DA

or

P=a+b+c+d

Here are two examples.

Find the perimeter of the parallelogram below.

Example 1, StudySmarter Originals

Example 1, StudySmarter Originals

Solution

To solve this, we shall simply add the dimensions of all four sides of this parallelogram.

P=17+17+11+11

P=2(17)+2(11)

P=34+22

P=56cm

Thus, its perimeter is 56cm.

Calculate the length of the missing side, x of the trapezoid below given that the perimeter is 51cm.

Example 2, StudySmarter Originals

Example 2, StudySmarter Originals

Solution

Using the formula for the perimeter of a quadrilateral, we find that

P=8+12+13+x

51=8+12+13+x

8+12+13+x=51

Now bringing 8, 12 and 13 to the right-hand side of this equation, thus making x the subject, we obtain

x=5181213

x=18cm

Therefore, the length of the missing side, x is 18cm.

Area of Quadrilaterals

The area of a quadrilateral is described by the space enclosed within its boundary. Each of the six types of quadrilaterals we have seen above has its own area formula. The table below presents their respective area formulas.

Quadrilateral

Area

Square

Area of a square, StudySmarter Originals

Area of a square, StudySmarter Originals

A=a×a=a2

where a is the length of each side.

Rectangle

Area of a rectangle, StudySmarter Originals

Area of a rectangle, StudySmarter Originals

A=a×b

where a and b are the lengths of width and height, respectively.

Parallelogram

Area of a parallelogram, StudySmarter Originals

Area of a parallelogram, StudySmarter Originals

A=a×h

where a and h are the lengths of width and height, respectively.

Trapezium

Area of a trapezium, StudySmarter Originals

Area of a trapezium, StudySmarter Originals

A=12×(a+b)×h

where a and b are the lengths of the bases (top and bottom parallel sides) and h is the height.

Rhombus

Area of a rhombus, StudySmarter Originals

Area of a rhombus, StudySmarter Originals

A=12×d1×d2

where d1 and d2 are the lengths of the vertical diagonal and horizontal diagonal, respectively.

Kite

Area of a kite, StudySmarter Originals

Area of a kite, StudySmarter Originals

A=12×d1×d2

where d1 and d2 are the lengths of the vertical diagonal and horizontal diagonal, respectively.

Let us look at two worked examples.

Find the area of the trapezium below.

Example 3, StudySmarter Originals

Example 3, StudySmarter Originals

Solution

From the diagram above we can deduce that

a=21cm

b=15cm

h=13cm

Now using the area formula for a trapezium, we obtain

A=12×(21+15)×13

A=12×(36)13

A=12×468

A=234cm2

Important note: Don't be confused by the length of the bases and legs! The parallel sides are the bases which are what we will use in our formula.

Thus the area is 234cm2.

Find the length of the horizontal diagonal, d of the rhombus below given that the area is 123.5cm.

Example 4, StudySmarter Originals

Example 4, StudySmarter Originals

Solution

Here, the vertical diagonal is 13cm. Using the area formula of a rhombus, we find that

A=12×13×d

123.5=12×13×d

13×d2=123.5

Now multiplying both sides by 2, we obtain

2(13×d2)=2(123.5)

13d=247

Then dividing both sides by 13, we get

13d13=24713

d=19cm

Thus, the length of the horizontal diagonal, d is 19cm.

Examples Involving Quadrilaterals

We shall end this topic with several worked examples of quadrilaterals that make use of the concepts we have established throughout this discussion.

Given the kite ABCD below, answer the following questions:

  1. Find the missing sides AD and AB, given that the perimeter is 88cm.

  2. Calculate the missing angles M and N.

  3. Are any of these sides parallel to each other?

Example 5, StudySmarter Originals

Example 5, StudySmarter Originals

Question 1

Firstly, note that AD=AB since a kite has two pairs of equal adjacent sides (the other being CB=CD).

AD=AB

x2=y4

y=x2+4

y=x+2

Now, given the perimeter and the sum of all its sides, we obtain

P=AB+AD+CD+CD

88=(y4)+(x2)+32+32

88=y+x6+64

Now substituting for y and solving this equation for x, we obtain

88=(x+2)+x6+64

(x+2)+x6+64=88

2x+60=88

2x=8860

2x=28

Now dividing both sides by 2, have

x=282

x=14

Thus, the lengths of AB and AD are

AB=y4

AB=(x+2)4

AB=(14+2)4

AB=12cm

Since AB=AD, thus AD is also 12cm.

Question 2

Recall that a kite has one pair of equal opposite angles that are obtuse. This means that M=N. Furthermore, that measures of the other two angles are given and the sum of all the interior angles of any quadrilateral is 360º. From here, we find that

DAB+BCD+M+N=360º

102º+51+M+N=360º

\implies 153º+2\angle M=360º\]

Now solving for M, we obtain

2M=360º153º

2M=207º

M=207º2

M=103,5º

Thus, both M and N are equal to 103.5º (since M=N).

Question 3

By the properties of a kite, there are no sides that are parallel to each other.

Given the parallelogram ABCD below, answer the following questions:

  1. Find the length of AB given that the perimeter is 40cm.

  2. Calculate the area of ABCD.

  3. Deduce the angle Y.

Example 6, StudySmarter Originals

Example 6, StudySmarter Originals

Question 1

Firstly, note that AB=DC and AD=BC since a parallelogram has two pairs of equal opposite sides. Given the perimeter and the sum of all its sides, we obtain

P=AB+AD+CD+CD

40=x+9+x+9

40=2x+18

Now solving this equation for x, we obtain

2x=4018

2x=22

x=222

x=11cm

Thus, the length of AB is 11cm.

Question 2

Here, the height is 7cm and the width is the length of side AB. We know that AB is equal to 11cm. Thus, by the area formula of a parallelogram, we have

A=11×7

77cm2

Thus, the area of ABCD is 77cm2.

Question 3

In this case, BCD and Y are supplementary since both these angles are on a straight line. Recall that two angles are supplementary when the sum of their measures is equal to 180º. Using this idea, we find that

BCD+Y=180º

114º+Y=180º

Now, rearranging this equation and solving for our missing angle, we obtain

Y=180º114º

Y=66º

Thus Y is equal to 66º.

Given the rectangle PQRS below, answer the following questions:

  1. Find the perimeter and area of PQRS.

  2. Calculate the length of the diagonal QS.

  3. How big is QSR?

Example 7, StudySmarter Originals

Example 7, StudySmarter Originals

Question 1

Firstly, note that PQ=SR and PS=QR since a rectangle has two pairs of equal opposite sides. Now, adding the lengths of all its sides, we obtain

P=PQ+QR+SR+PS

P=15+8+15+8

P=46cm

Here, the length is 15cm and the height is 8cm. So by the area formula of a rectangle, we find that

A=15×8

A=120cm2

Thus, the perimeter is 46cm and the area is 120cm2.

Question 2

By the properties of a rectangle, recall that it has 4 right angles. Notice that the diagonal QS creates a right-angle triangle QRS where QRS is equal to 90º. Thus, we can use Pythagoras' Theorem to find the length of QS. Here, QS is the hypotenuse and the two sides are QR=8cm and SR=15cm. By doing so, we get

QS2=QR2+SR2

QS2=82+152

QS2=64+225

QS2=289

We will only consider the positive root since we are dealing with measurements. Then

QS=289

QS=17cm

Thus, the diagonal, QS is equal to 17cm.

Question 3

Here, PSQ and QSR are complementary since both these angles lie at a right angle. Recall that two angles are complementary when the sum of their measures is equal to 90º. With that, we have

PSQ+QSR=90º

66º+QSR=90º

Now, rearranging this equation and solving for our missing angle, we obtain

QSR=90º66º

QSR=24º

Thus QSR is equal to 24º.

Quadrilaterals - Key takeaways

  • A quadrilateral is a polygon with four sides, four vertices and four angles.
  • A quadrilateral has two diagonals.
  • The sum of all the interior angles of a quadrilateral is 360º.
  • There are six types of quadrilaterals: square, rectangle, parallelogram, trapezium, rhombus and kite.
  • The perimeter of a quadrilateral is the sum of all its sides, i.e. P=a+b+c+d
  • Area formula for quadrilaterals

    Quadrilateral

    Area

    Square

    A=a×a=a2

    Rectangle

    A=a×b

    Parallelogram

    A=a×h

    Trapezium

    A=12×(a+b)×h

    Rhombus

    A=12×d1×d2

    Kite

    A=12×d1×d2

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Quadrilaterals
Frequently Asked Questions about Quadrilaterals

What is a quadrilateral? 

A quadrilateral is a polygon with four sides, four vertices and four angles.

What are the types of a quadrilateral? 

There are six types of quadrilaterals: square, rectangle, parallelogram, trapezium, rhombus and kite.

What are examples of a quadrilateral? 

Examples of quadrilaterals: square, rectangle, parallelogram, trapezium, rhombus and kite.

What are the properties of a quadrilateral? 

  1. Four sides; 

  2. Four vertices;

  3. Two diagonals;

  4. The sum of all their interior angles is 360o.

What is the area of the quadrilateral? 

The area of a quadrilateral is the space enclosed within its boundary. It is the product of its width and height.

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