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Fig. 1 - The concept of power is used differently in daily life and physics. In physics, power is the rate at which a force does work.
But what does 'power' mean in physics? In physics, being powerful means doing work as quickly as possible. For example, Mark carries a box of books from the ground floor of the school to the 2nd floor in 1 minute. If Kevin does the same work in 2 minutes, Mark displays more mechanical power than Kevin.
Mechanical Power Definition
Let's look into the definition of power.
Power is the rate at which a force does work.
It is helpful to keep track of how fast the energy of a system changes with time. A system can receive energy and can transfer it to other systems as well. Energy can be converted from one type of energy to another. For example, kinetic energy can be converted into heat. Power is a time-dependent physical quantity. For example, your power also changes if you take a different amount of time to get the work done.
Mechanical Power Formula
Work is the change of energy in a system when a force acts on it. If a force does an amount of work \(W\) in a time interval, we can calculate the average power due to the force as
\[\begin{align}P_{\text{avg}}&=\frac W{\Delta t},\\P_{\text{avg}}&=\frac{\Delta E}{\Delta t}.\end{align}\]
On the other hand, the instantaneous power is the instantaneous time rate of doing work. We can calculate it from
\[P=\frac{\text dW}{\text dt}.\]
Instantaneous power is useful when we have a work function dependent on time, and we want to know the power at a specific instant. Then we take the time derivative of the work function and plug the instant time into the derived function.
The SI unit of power is the joule per second \(\mathrm{J\, s^{-1}}\), which is also called the watt \(W\) after James Watt.
The rate at which a force does work on a particle (or particle-like item) may be expressed in terms of the force and the particle's velocity. For a particle traveling in a straight path and subjected to a constant force \(\vec{F}\) directed at an angle \(\theta\) to that path, we can write the power equation as:
$$\begin{align*}P&=\frac{\text{d}W}{\text{d}t},\\P&=\frac{F\cos{\theta}\text{d}x}{\text{d}t},\\P&=F\cos{\theta}\left(\frac{\text{d}x}{\text{d}t}\right),\\P&=Fv\cos{\theta}.\end{align*}$$
We must notice that the component of the force that acts along the direction of displacement is the one responsible for doing work and moving the object. If we reorganize the equation according to the dot product, we end up with: \(P=\vec{F}\cdot\vec{v}.\)
Mechanical Power Example
Let's look at examples of mechanical power.
A block is moving on a frictionless floor with the effect of force \(F = 20\,\text{N}\) with a speed of \(v=5\,\frac{\text{m}}{\text{s}}\) instantaneously as shown in figure 2. What is the power due to the force acting on that block at that instant?
Answer:
To find instantaneous power, we need the magnitude of the force acting on the object, and the instant speed. The force acts on the box at \(60^\circ\). Because the vertical component of the force does not do work, we need the horizontal component to find the instantaneous power. We can calculate it using the equation \(P=Fv\cos{\theta}\). We know that the force is \(F=20\,\text{N}\) and the velocity is \(v=5\,\frac{\text{m}}{\text{s}}\). If we insert these known values into the formula, we can calculate the instantaneous power:
\begin{align*}P&=\left(20\,\text{N}\right)\left( 5\,\frac{\text{m}}{\text{s}}\right) \cos{60^\circ},\\P&=\left(20\,\text{N}\right)\left( 5\,\frac{\text{m}}{\text{s}}\right)\left(\frac12\right),\\P&=50\,\text{W}.\end{align*}
Since the rate of transfer of energy is different than zero, the velocity will increase.
Let's look at one more example where two forces are acting.
A block is moving on a frictionless floor with a force of \(F_1=20\,\text{N}\) at an angle of \(60^\circ\) with the floor, and the second force of \(F_2=10\,\text{N}\) pulling directly to the left as shown in figure 3. The block is moving at a speed of \(5\, \frac{\text{m}}{\text{s}}\) instantaneously.
What is the net power due to the forces acting on that block at that instant?
Answer:
Let's calculate the instantaneous power of the individual forces.
First, calculate the instantaneous power \(P_1\) due to \(F_1\):
\begin{align*}P_1&=F_1 v\cos{60^\circ},\\P_1&=\left(20\,\text{N}\right) \left(5\,\frac{\text{m}}{\text{s}}\right)\left(\frac12\right),\\P_1&=50\,\text{W}.\end{align*}
Then, calculate the instantaneous power \(P_2\) due to \(F_2\):
\begin{align*}P_2&=F_2 v\cos{180^\circ},\\P_2&=\left(10\,\text{N}\right) \left(5\,\frac{\text{m}}{\text{s}}\right)\left(-1\right),\\P_2&=-50\,\text{W}.\end{align*}
To find the net power, we can add up \(P_1\) and \(P_2\):
\begin{align*}P_{\text{net}}&=P_1+P_2,\\P_{\text{net}}&=50\,\text{W}-50\,\text{W},\\P_{\text{net}}&=0.\end{align*}
Since the net power is zero, that means the rate of transfer of kinetic energy is zero as well. So, the speed of the block will remain the same.
Mechanical Power Output
We can study the power of a mechanical system by splitting it into input power and output power. The output power will always be equal to or smaller than the input power, as, in real life, machines use energy to do work. The input power refers to how much energy a system can receive, while the output power refers to how much energy the system can use to do work. Let's say that the input force \(F_{\text A}\) acts on a system that moves with velocity \(v_{\text A},\) and the output force \(F_{\text B}\) acts on a system that moves with velocity \(v_{\text B}\). If the system does not lose any mechanical power, then the input and output power are equal:
$$F_{\mathrm A}v_{\mathrm A}=F_{\mathrm B}v_{\mathrm B.}$$
This case allows us to create an expression for the mechanical advantage \(a\), which is another way of measuring the output energy in terms of the input energy or the efficiency \(e\):
$$\begin{align*}a&=\frac{F_{\mathrm B}}{F_{\mathrm A}},\\a&=\frac{v_{\mathrm B}}{v_{\mathrm A}},\\e&=\frac{\text{output energy}}{\text{input energy}}\times100\%.\end{align*}$$
Even if energy cannot be destroyed, it can be converted to a different type of energy. As a consequence, the efficiency of the device is slower, as the output is less than the input. For example, a light bulb's input power is provided by electrical energy, while its output power is in the form of light and heat.
Determine the efficiency of a light bulb that releases \(60\,\text{kJ}\), while its input energy is \(1550\,\text{kJ}\).
Answer:
The efficiency of the light bulb is given by
$$\begin{align*}e&=\frac{60\,\text{kJ}}{1550\,\text{kJ}}\times 100\%,\\e&=3.87\%.\end{align*}$$
The lightbulb is very inefficient.
Difference Between Mechanical and Electrical Power
While mechanical power refers to the rate at which work can be done, electrical power is the rate at which an electric circuit transfers electrical energy. An electric motor's input power is provided by electrical power, while the output power is mechanical so that it causes the car to move. The equation for electrical power is given by
$$P=IV,$$
where the electrical current \(I\) is expressed in amperes \(\left(\text A\right)\) and the applied voltage is expressed in volts \(\left(\text V\right)\).
We have previously discussed mechanical power for translational motion. Motors undergo rotational motion so that we can express the rotational form of mechanical power. It depends on the rotational analogous to the force and velocity, which are the torque and the angular velocity:
$$P=\tau \omega.$$
Mechanical Power - Key takeaways
- The power due to the force is defined as the rate at which a force does work.
- If a force does an amount of work W in a time interval, then average power can be calculated from \(P=\frac{W}{\Delta t}\).
- The instantaneous power is the instantaneous time rate of doing work, \(P=\frac{\text dW}{\text dt}\).
- The rate at which a force does work on a particle (or particle-like item) may alternatively be expressed in terms of the force and the particle's velocity: \(P=\vec{F}\cdot\vec{v}\).
References
- Fig. 1 - The concept of power is differently used in daily life and physics. In physics, power is the rate of doing work (https://pixabay.com/es/photos/hombre-persona-poder-fuerza-fuerte-1282232/), by Pexels (https://pixabay.com/es/users/pexels-2286921/), licensed by Pixabay (https://pixabay.com/es/service/license/)
- Fig. 2 - The block is moving on a frictionless floor under the effect of a force. The force has both vertical and horizontal components, StudySmarter Originals
- Fig. 3 - A block is moving on a frictionless floor. Two forces act on the object in opposite directions, StudySmarter Originals
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Frequently Asked Questions about Mechanical Power
What is meant by mechanical power?
Mechanical power is the rate that a force does work on an object. It is the amount of energy transferred into a system over a period of time.
How do you calculate mechanical power?
You calculate mechanical power by doing the work divided by the amount of time that the work was being done.
What are the types and uses of mechanical power?
Some types of mechanical power are water turbines, electric motors, hydraulic presses, steam turbines, and wind turbines. The power that these machines produce is used to power our transportation, electricity, and other necessities.
What is the difference between mechanical and electrical power?
While mechanical power refers to the rate at which work can be done, electrical power is the rate at which an electric circuit transfers electrical energy.
What is the formula for mechanical power?
Mechanical power equals the change in energy divided by the change in time. It can also be expressed as the work divided by the change in time.
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