Phase Angle

Phase Angle

In previous articles, we discussed the differential equation that describes oscillatory movement, particularly simple harmonic motion. We know the solution that satisfies the equation is expressed as

$$x=A\sin\left(\omega t+\phi_0\right).$$

Where \(A\) is the amplitude in meters \((\mathrm m)\), \(\omega\) is the angular frequency in radians per second \((\frac{\mathrm{rad}}{\mathrm s})\), and \(\phi_0\) is the initial phase in radians \((\mathrm{rad})\).

The phase angle is the angular component of a periodic wave, such that it is defined as the argument of the sine function, \(\omega t+\phi_0\). By choosing \(\phi_0\), we specify the oscillating object's initial position to make sure we have the correct equation with the oscillator's position, no matter where it may have been located at \(t=0\). We can restate the above equation in terms of the symbol \(\phi\) for the phase angle.

$$\begin{align*}\phi&=\omega t+\phi_0,\\x&=A\sin\left(\phi\right).\end{align*}$$

To determine the initial phase we use the following formula:

$$\phi_0=\sin^{-1}\left(\frac{x_0}A\right),$$

where \(A\) is the amplitude in meters \((\mathrm m)\) and \(x_0\) is the initial position of the object at \(t=0\) in meters \((\mathrm m)\).

The initial phase will determine if a sine or cosine function is used to describe the position of the oscillating object. For example, if \(\phi_0=\frac\pi2\) we can use a cosine function instead of a sine function with the initial phase. This is due to the trigonometric identity, \(\sin\left(\frac\pi2+\theta\right)=\cos\left(\theta\right)\). The table below clarifies how the two expressions yield the same results at any time.

As a side note, the phase angle plays a very important role in experimental physics, especially in electronics where there is a direct relationship between the voltage and sinusoidal functions. In electronics, the phase angle refers to the angular displacement between the voltage and current waveforms in an alternating current circuit.